题目来源:
https://leetcode.com/problems/recover-binary-search-tree/
题意分析:
二叉搜索树中有两个点错了位置,恢复这棵树。
题目思路:
如果是没有空间复杂度限制还是比较简单。首先将树的值取出来,然后排序,将相应的位置判断是否正确。如果要特定空间复杂度就难很多。
代码(python):
![](https://images.cnblogs.com/OutliningIndicators/ContractedBlock.gif)
![](https://images.cnblogs.com/OutliningIndicators/ExpandedBlockStart.gif)
# Definition for a binary tree node.# class TreeNode(object):# def __init__(self, x):# self.val = x# self.left = None# self.right = Noneclass Solution(object): def recoverTree(self, root): """ :type root: TreeNode :rtype: void Do not return anything, modify root in-place instead. """ ans,ansr = [],[] def solve(root): if root: solve(root.left) ans.append(root.val);ansr.append(root) solve(root.right) solve(root) ans.sort() for i in range(len(ans)): ansr[i].val = ans[i]